Originally posted by ArmySGT.
View Post
Announcement
Collapse
No announcement yet.
Warhead data
Collapse
X
-
so how about this.....
M67 Fragmentation grenade..
using the spherical charge equation.
(7620/(7620/0.333)=((0.1/0.18)+3/5)-1/2 <--- that in negative one half as an exponent.
22882 = 0.65555555555555555555555555555556
Fragment is moving a 0.66 meters per second
But, then E-factor is based on speed and diameter of the projectile..... without weight as a factor.
Comment
-
Originally posted by mmartin798 View PostI think your algebra is off. I solved the equation for V and got the equation below.
Substituting the values I get V = 2730 m/s
So, with a velocity.... we need a diameter for the e-factor formula.
Modern grenade 1mm or 0.5 mm for a fragment.......
WW2 grenade, 3mm 5mm
Comment
-
We might not need to know the size, but use a modified E-Factor calculation. The E-Factor is a measure of the wound cavity. As wound cavity is caused mostly by momentum conservation and transfer, it is the momentum of the fragment that matters. Momentum is just mass x velocity, which we have for fragmentation. We just need to find how the bullet diameter is related to mass and make the substitution.
Edit
Been giving this some more thought. We really don't need to mess with the formula if we have an idea of the fragment size, and that size can be calculated if we make some assumptions. If we assume the fragments are roughly cylindrical with diameter approximately the same as the height, we can use the density of steel and the mass we know to calculate the volume and extrapolate the dimensions. Sounds like a lunch time project.
Comment
-
Originally posted by ArmySGT. View PostSo, with a velocity.... we need a diameter for the e-factor formula.
Modern grenade 1mm or 0.5 mm for a fragment.......
Mass of an M67 fragment = 0.1 g
Volume of an M67 fragment = 0.1/8.05 = .01242 cm^3
Volume of a cylinder is given by:V= pi * r^2 * h
Assuming height equals diameter gives:V = pi * r^2 * 2 * rV = 2 * pi * r^3
Solving for r gives:r = (V/(2*pi))^(1/3)
Doing the substitutions and doubling the radius to get the diameter and height we get 0.251 cm or 2.51 mm
If we assume a softer steel with a density of 7.75 g/cm^3, the diameter comes to 2.54 mmLast edited by mmartin798; 02-17-2016, 11:41 AM.
Comment
-
Damn, that gives an M67 fragmentation grenade an Efactor of 18 per fragment and you roll 1d20 to determine the number of fragments that hit the target.
Guess, players aren't going to shrug that off like they did with resistweave and the old 4 points per fragment.
Comment
-
Originally posted by ArmySGT. View PostDamn, that gives an M67 fragmentation grenade an Efactor of 18 per fragment and you roll 1d20 to determine the number of fragments that hit the target.
Guess, players aren't going to shrug that off like they did with resistweave and the old 4 points per fragment.
This means one of two things. We may need to adjust the number of fragments that strike a person to something lower or we just start carrying a big bag of M67s and lots of body armor.
Comment
-
For those who want to calculate values for other grenades, here is a spreadsheet you can use. Remember the assumptions used in these calculations are that the fragments are generated from a wire coil and the fragments are all uniform and the same length as the diameter of the wire. The fragments are therefore short cylinders and have a drag coefficient of 1.15.Attached Files
Comment
-
Originally posted by nuke11 View PostYes this is still my current work. I've been digging around for Soviet information, but it seems to be a bit harder to find for some reason.
I got it off of Scribd.... Which has been a good source for these.
Comment
-
Ok, the problem you have at the moment is the document is based on TNT equivalent of an RE of 1.00. The game uses C4 as it's equivalent for an RE of 1.00 and TNT has an RE of 0.75 in the game.
You will need to adjust all of the formulas from the document accordingly.
Doesn't the M67 have a solid steel case that also needs to be taken into account for the fragments Here is a good website that shows what some of the fragments look like: http://machinesforwar.blogspot.ca/2012/03/m67.html
Some more images of the inside of the case and what the fragments look like: http://www.big-ordnance.com/grenades...CutawayM67.jpg and http://www.big-ordnance.com/grenades/loworderM67.JPG
The M26 is the grenade with a spiral wound wire core: http://img.photobucket.com/albums/v1...ut/OR-034A.jpgLast edited by nuke11; 02-17-2016, 07:39 PM.
Comment
-
Originally posted by nuke11 View PostOk, the problem you have at the moment is the document is based on TNT equivalent of an RE of 1.00. The game uses C4 as it's equivalent for an RE of 1.00 and TNT has an RE of 0.75 in the game.
You will need to adjust all of the formulas from the document accordingly.
Originally posted by nuke11 View PostDoesn't the M67 have a solid steel case that also needs to be taken into account for the fragments Here is a good website that shows what some of the fragments look like: http://machinesforwar.blogspot.ca/2012/03/m67.html
Some more images of the inside of the case and what the fragments look like: http://www.big-ordnance.com/grenades...CutawayM67.jpg and http://www.big-ordnance.com/grenades/loworderM67.JPG
The M26 is the grenade with a spiral wound wire core: http://img.photobucket.com/albums/v1...ut/OR-034A.jpg
Comment
Comment